Why does this stylesheet produce the output "Milwaukee",
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes" encoding="UTF-8" />
<xsl:template match="/">
<xsl:apply-templates select="rowset">
<xsl:with-param name="st" select="'WI'" />
</xsl:apply-templates>
</xsl:template>
<xsl:template match="rowset">
<xsl:param name="st" />
<xsl:value-of select="row[state='WI']/city" />
</xsl:template>
</xsl:stylesheet>
and this one, only '<?xml version="1.0" encoding="UTF-8" ?>',
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes" encoding="UTF-8" />
<xsl:template match="/">
<xsl:apply-templates select="rowset">
<xsl:with-param name="st" select="'WI'" />
</xsl:apply-templates>
</xsl:template>
<xsl:template match="rowset">
<xsl:param name="st" />
<xsl:value-of select="row[state='$st']/city" />
</xsl:template>
</xsl:stylesheet>
To save you the trouble of minutely examining the two, the difference is
that in the one that doesn't work the way I think it should, I use the >
value of the parameter to test the content of the "state" element, where in
the one that produces the output I want, I use the literal string
'WI'.
No, in the second template you are comparing state to the string '$st':
<xsl:value-of select="row[state='$st']/city" />
and there is no "state" element in your source.xml with string value "$st".
Must be:
<xsl:value-of select="row[state=$st]/city" />
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list