If you're restricted to XSLT 1.0, use a recursive template or an
xx:tokenize() extension function to break the text into words, then test
each word to see if it starts with "http://"; or "HTTP://".
Michael Kay
Of course, you're right. Any url's that don't start with
http:// or href will be ignored. What I want to do is take
an xml file like this:
<document>
<longstring>for more information look here: http://url.com
for other products look here: http://moreinformation.com to
see a review go here: http://www.review.com. </longstring> </document>
and translate it into this:
<document>
<url>http://url.com</url>
</document>
<document>
<url>http://moreinformation.com</url>
</document>
<document>
<url>http://www.review.com</url>
</document>
Thanks
"Michael Kay"
<mhk(_at_)mhk(_dot_)me(_dot_)uk> To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent by: cc:
owner-xsl-list(_at_)lists(_dot_)mulbe
Subject: RE: [xsl] How can I return all urls in a string
rrytech.com
09/28/2003 04:15 PM
Please respond to xsl-list
Please try to explain you question more clearly. What are you
trying to do? What do you mean "Obviously I know the url will
start with 'http://'
- how do you know this? (Many URLs do not start with this string).
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf
Of Brian
Benson
Sent: 28 September 2003 18:42
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How can I return all urls in a string
I'm not sure how to do this. Obviously I know the url will
start with
"http://"; but I don't know what it will end with. Any thoughts or
pointers are appreciated.
Thanks
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