Hi David,
I'll reproduce my sample output so it shouldn't wrap.
-----------
Marital Status
marriage (1997-01-15)
divorce (1993-06-24)
marriage (1989-04-11)
Date of Birth
1968-04-05
Religion
Lutheran (1996-12-02)
Roman Catholic (1968-04-05)
----------------
Of course, the columns would appear next to each other, so it would
appear as
-------------
Marital Status Date of Birth Religion (etc..)
-------------
However, the refDate attributes on maritalStatus and religion are
not tied to each other. The refDates for all five elements can be
different as they are above, yet both columns have to be sorted.
Thanks for the reply,
--Ryan
David Carlisle wrote:
Your sample output got wrapped which made it a bit confusing but i
think yprobbaly your religion field alwas has a date that ties it to
marital status, so
<xsl:for-each select="$left">
<xsl:sort select="@refDate"/>
<xsl:variable name="for-each-pos" select="position()" />
<xsl:variable name="date" select="@refDate" />
<xsl:call-template name="print-entry">
<xsl:with-param name="entry" select="$left[ $for-each-pos ]"/>
</xsl:call-template>
<xsl:call-template name="print-entry">
<xsl:with-param name="entry" select="$middle[ $for-each-pos ]"/>
</xsl:call-template>
<xsl:call-template name="print-entry">
<xsl:with-param name="entry" select="$right[(_at_)refDate=$date"/>
</xsl:call-template>
<xsl:text> </xsl:text>
</xsl:for-each>
________________________________________________________________________
This e-mail has been scanned for all viruses by Star Internet. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list