Herez the piece of code.
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:param name="userid" select="xyz(_at_)yahoo(_dot_)com"/>
<xsl:template match="/">
<xsl:if test="contains($userid, 'yahoo')">
<!-- Goto http://www.yahoo.com -- >
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Hope this helps,
Basically i want this xsl to redirect to different
pages depending on the domain name in the userid.
Thanks,
Archana
--- Michael Kay <mhk(_at_)mhk(_dot_)me(_dot_)uk> wrote:
So i know what the username is, now my problem is
i am
trying to open up www.yahoo.com if the username is
xyz(_at_)yahoo(_dot_)com and www.hotmail.com if the username
has xyz(_at_)hotmail(_dot_)com(_dot_)
I know i can use <xsl:if test="contain($username,
'yahoo')"> to check for the username, but then i
don't
know how to specify in the <xsl:if> to open up
www.yahoo.com.
Hope you understood my problem.
No, sorry, I don't. I haven't the faintest idea what
you mean by
"opening up www.yahoo.com". XSLT transforms a source
tree into a result
tree, where does "opening up" a web site fit into
this?
Michael Kay
XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
__________________________________
Do you Yahoo!?
Yahoo! SiteBuilder - Free, easy-to-use web site design software
http://sitebuilder.yahoo.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list