Hi Elena,
most probably you are on the wrong level.
Suppose you have an template matching the
element "l". You didn't show the code!
<xsl:template match="l">
<xsl:choose>
<xsl:when test="l[(_at_)part='I']">
===================>Here you assume l has an element l
===================>match the attribute directly
<xsl:when test="@part='I'">
...
Cheers,
Juergen
-----Ursprüngliche Nachricht-----
Von: Elena Pierazzo [mailto:pierazzo(_at_)ital(_dot_)unipi(_dot_)it]
Gesendet am: Mittwoch, 24. September 2003 13:02
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: [xsl] matching elements with no attributes
Hi all,
Is there a way to match an element just when the element itself has no
attributes?
For example, in my text I have:
<l>bla bla bla</l>
<l part='F'>bla bla</l>
<l part='I'>bla bla</l>
I want to declare different rules for <l> when it has no attributes and
when he has attributes. I've tryed using
<xsl:choose>
<xsl:when test="l[(_at_)part='I']">
bla
</xsl:when>
<xsl:when test="l[(_at_)part='F']">
bla
</xsl:when>
<xsl:otherwise> <-- used for an l element with no attributes -->
bla
</xsl:otherwise>
</xsl:choose>
but it doesn't work because I need to declare the same variable for the
first xsl:when and for the xsl:otherwise.
Suggestions?
Many tanks in advance
Elena Pierazzo
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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