<xsl:if test="ParaItem">
</xsl:if>
should do what you desire..
for e.g. (just assuming for -- that the context node
will be Paragraph)
<xsl:for-each select="Paragraph">
<xsl:if test="ParaItem">
<!-- some processing -->
</xsl:if>
</xsl:for-each>
You need to give more details for somebody to be more
specific!
Regards,
Mukul
--- "SANWAL, ABHISHEK (HP-Houston)"
<abhishek(_dot_)sanwal(_at_)hp(_dot_)com> wrote:
Hmm.. is that so ?
Because my current node will be <Paragraph> and not
<paraitem>.
Also, it can have other elements as children. So I
need to have a
specific "test" that checks if that child exists
before APPLYING
stylesheets for that child.
<Paragraph>
<ParaItem>
<ParaItem>
<ParaItem>
....
<Paragraph>
Let me know :). Is there a better expression to
check if the current
NODE (paragraph) contains ATLEAST one child
PARAITEM.
:)
Thanks,
Abhishek Sanwal
HP - Houston Campus
abhishek(_dot_)sanwal(_at_)hp(_dot_)com
-----Original Message-----
From: Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com
[mailto:Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com]
Sent: Thursday, September 18, 2003 12:42 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] determining if one or more
instances of a child are
present in the current node element
Hi,
<xsl:if test="count(child::*[name()=('ParaItem')])
>=1">
<!-- Check if this expression is correct -->
Is this expression correct in being able to
determine if the current
node has one or more instances of the child
ParaItem?
Yes, but the easies way would be just to test with
<xsl:if test="ParaItem"/>
Cheers,
Jarno - VNV Nation: Amhrain Comhrac
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