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RE: Do something if no items in for-each meet criteria

2003-09-11 16:57:09

Hi,
   Here is a possible solution, create a variabe to record the result of
"for-each" statement and test the length of the variable. It might not be
the perfect one. but it can get the desired result.

<xsl:transform xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
version='1.0'
xmlns:lang='en'

        <xsl:template match="/">
                <xsl:variable name="noFurry">
                        <xsl:for-each select="//animal">
                                <xsl:if test="furry = 'true'">
                                        <xsl:value-of select="type"/><br/>
                                </xsl:if>
                        </xsl:for-each>
                </xsl:variable>

                <xsl:if test="string-length($noFurry) = 0">
                        <xsl:message>None are furry</xsl:message>
                </xsl:if>
        </xsl:template>
</xsl:transform>

Lisa

Software Engineer
Galdos Systems Inc

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]On Behalf Of 
Peter
Hollingsworth
Sent: Thursday, September 11, 2003 4:12 PM
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Do something if no items in for-each meet criteria


I'm trying to
   1) go through a set of nodes
   2) if any matches my criteria, display it
   3) if NONE matches my criteria, display a message like "None"

For example, imagine this xml listing some animals:
<animal>
   <type>snake</type>
   <furry>false</furry>
</animal>
<animal>
   <type>fish</type>
   <furry>false</furry>
</animal>

and this XSL that lists all the ones with fur:
The following animals are furry:<br/>
<xsl:for-each select="animal">
   <xsl:if test="furry = 'true'">
     <xsl:value-of select="type"/><br/>
   </xsl:if>
</xsl:for-each>
[if no animals were furry, print "None are furry"]  <---how can I do this?

Any way I can accomplish what I'm trying to do on the last line above?

Thanks.

--Peter


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