Use the identity template and override it for nodes that have "bar" or
"item" children like this:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="node()[bar or item]">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates>
<xsl:sort select="@id" data-type="number"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on your source.xml:
<foo>
<bar id="2">
<item id="6">hello</item>
<item id="4">world</item>
</bar>
<bar id="1">
<item id="7">how's</item>
<item id="3">life</item>
</bar>
</foo>
the wanted result is produced:
<foo>
<bar id="1">
<item id="3">life</item>
<item id="7">how's</item>
</bar>
<bar id="2">
<item id="4">world</item>
<item id="6">hello</item>
</bar>
</foo>
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
"marcel salathe" <ms7141(_at_)gmx(_dot_)de> wrote in message
news:5295(_dot_)1063122940(_at_)www25(_dot_)gmx(_dot_)net(_dot_)(_dot_)(_dot_)
Hi
I have a XSL question which might be easy to answer, but I couldnt.
Suppose I have an XML document like this:
<foo>
<bar id="2">
<item id="6">hello</item>
<item id="4">world</item>
</bar>
<bar id="1">
<item id="7">how's</item>
<item id="3">life</item>
</bar>
</foo>
Now I want to sort the bar elements and then the item elements according to
their Id's, and finally output
the entire document sorted, e.g.
<foo>
<bar id="1">
<item id="3">life</item>
<item id="7">how's</item>
</bar>
<bar id="2">
<item id="4">world</item>
<item id="6">hello</item>
</bar>
</foo>
I could achieve sorting or copying, but I couldnt do both together. I guess
it must be quite a simple
XSLT.
Any help very much appreciated.
Best regards,
marcel
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