Hi,
the position of <lid> is the number of preceding siblings.
In your example should be 4, <loc>, <sub>, <date> sibling before.
Maybe you can use a foreach with select="//lid".
All the lid elements in a node set in document order.
Then you can use position() within the loop.
But I don't understand your questions fully.
What do you want to achieve?
Kind regards,
Juergen
-----Ursprüngliche Nachricht-----
Von: M. David Peterson [mailto:conners_dad(_at_)msn(_dot_)com]
Gesendet am: Dienstag, 9. September 2003 07:23
An: xsl-list
Betreff: [xsl] limit count() to nodes with a position() < the postion
of the current node
Hi all,
Ive got an interesting one for you...
Ive got the following key...
<xsl:key name="linkCount" match="lid" use="."/>
that uses the following xml...
<history>
<visit>
<loc>life</loc>
<subloc>main</subloc>
<date>9/8/2003 10:49:58 PM</date>
<lid>AAD001</lid>
</visit>
</history>
to give me the total count of all nodes that have the value of the current
context...
<xsl:value-of select="count(key('linkCount', lid))"/>
This works perfectly as it returns the total count of all nodes that have the
same value as the current context node...
But I want to take this one step further and return the count of all nodes that
have a position() that is less than the position of the current node. Taking
the position() of the context node out of the equation I thought it would as
simple as this (I used 5 as a test parameter)...
<xsl:key name="linkCount" match="lid[position() < 5]" use="."/>
I expected it to return the count of the nodes that matched the current
context node as long as there postion was less than 5. But it didn't. It
returned the total count for the entire xml tree.
So, my questions are... 1)What do I need to change to get the above example
to work and 2)How could I then take it one step further and use the
position() of the current context node as the parameter to test against the
position() of the test nodes?
Your help is much appreciated!
Best Regards,
M.David
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