This isn't a good way to tackle this requirement.
exsl:evaluate() does say that all the variables are accessible, but you
might find implementations that aren't conformant with this; it's a
heavy overhead for processor to have to maintain so much context at
run-time.
Better to do it in pure XSLT. Rather than declaring several variables
with semantics hidden in the choice of variable names, use the power of
XML to declare a composite (tree-structured) variable, and access it's
components using path expressions. Unfortunately you will also need the
node-set extension.
<xsl:variable name="participants">
<p nr="1">Absolute Relation</p>
<p nr="2">Relative Relation</p>
</xsl:variable>
<xsl:value-of select="xx:node-set($participants)/p[(_at_)nr=$type]"/>
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Cao Hui
Sent: 08 September 2003 09:35
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] how to evaluate a dyna generated variable?
Hello,
I have defined the I18n resources with variables like this:
<xsl:variable name="lang.type.participant.1"
select="'Absolute Relation'"/> <xsl:variable
name="lang.type.participant.2" select="'Relative Relation'"/>
<xsl:variable name="lang.type.participant.3" select="'Group
Expression'"/>
and in my stylesheet, I want to get the resource like this:
<xsl:value-of
select="exsl:evaluate(concat('$lang.type.participant.',Type))">
but it seems exsl:evaluate only accept variables that contain
XPath reference,right? then is there any way to do this?
Thanks
Max Cao
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