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RE: Date Format in XSLT

2003-09-04 07:41:25
If the names are all three characters, use

substring("JanFebMarApr....", ($month-1)*3+1, 3)

Michael Kay

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com 
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
michel geadah
Sent: 04 September 2003 13:47
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Date Format in XSLT


hi,

I need to transform the month to words.
For example, if i have '1' i need to output 'Jan', if i have 
'2' i need to 
output 'Feb', and so on...
(That is to say if i have 1-12-2003 i need it to be transformed to 
1-Dec-2003)

Thanks...
Michel

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