Team,
I have a xsl stylesheet that has a template with following statements:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
<xsl:template match="/newsletter">
..
..
..
<xsl:variable name="classification"
select="normalize-space(metadata/article-classification/.)"/>
<xsl:if test="contains($classification,'News')">
When I run the stylesheet with an XML file, I get following error:
got an exception....Unknown error in Xpath
; SystemID: file:..... Line#: 365; Column#: 98
Line 365 is the <xsl:variable....> line.
If I run it without this statement, it runs fine. I don't see any obvious error
in that statement. Any clues?
Thanks
Vivek
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list