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RE: Xml to Xml

2003-10-31 06:13:42
Write an identity template rule that copies elements:

<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>

And an empty template rule that skips the others:

<xsl:template match="V|U"/>

Michael Kay

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com 
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
poppe chris
Sent: 31 October 2003 12:20
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Xml to Xml




Hello i want to converse an xml doc to an other one but 
leaving out some 
elements, ive tried several ways but it just wont work,

here's what the original xml looks like
<?xml version="1.0"?>
<Bitstream xml:base="../CONTENT/final.yuv" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; xmlns="YUV" 
xmlns:yuv="YUV" xsi:schemaLocation="YUV 
file:/D:/school/DIA-BSDL-1%5B1%5D.1/DELIVERY_2003_08_13/BSDLSo
urce/../CONTENT/SCHEMAS/YUV.xsd">
        <Frame>
                <Y>
                        <Ysample>0 811008</Ysample>
                </Y>
                <V>
                        <Vsample>811008 405504</Vsample>
                </V>
                <U>
                        <Usample>1216512 405504</Usample>
                </U>
        </Frame>
        <Frame>
                <Y>
                        <Ysample>1622016 811008</Ysample>
                </Y>
                <V>
                        <Vsample>2433024 405504</Vsample>
                </V>
                <U>
                        <Usample>2838528 405504</Usample>
                </U>
        </Frame>
</Bitstream>

now i want the same but withouth the V and U elements and their children

thus something like
<Bitstream ...>
  <Frame>
     <Y>   <Ysample>...</Ysample></Y>
  </Frame>
  ...
</Bitstream>

thanks in advance,
Chris

_________________________________________________________________
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