I copied and pasted the xslt code from your last message.
The transformation performs OK with Saxon 6.5.3, Saxon 7.7, Msxml3, Msxml4,
XalanJ 2.4.1, XalanC 1.5, MS .Net xsltTransform.
This means that you're using a buggu XSLT processor.
Why don't you use one of the listed above?
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
"Sindigi, Ganesh K" <SindiGK(_at_)LOUISVILLE(_dot_)STORTEK(_dot_)COM> wrote in
message
news:0809DC8497D26748A7B1F36D36BC80A8AB3BD8(_at_)hqemailc(_dot_)louisville(_dot_)stortek(_dot_)com(_dot_)(_dot_)(_dot_)
Dimitre,
I tried with org.apache.xalan.xslt.Process class that is shipped along
with
JDK1.4.0_01. Is there any alternative way to resolve this ?
I used same code which is as below:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:my="my:my"
exclude-result-prefixes="my"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<my:elNames>
<name>id</name>
</my:elNames>
<xsl:variable name="elNames"
select="document('')/*/my:elNames/name"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:choose>
<xsl:when test="not(name() = $elNames)">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="*[name() = $elNames]"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="{name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="value">
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)yahoo(_dot_)com]
Sent: Thursday, October 30, 2003 12:20 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Re: Re: Converting specific child elements into attriutes
of parent
Sorry, I cannot reproduce the problem -- the transformation runs OK and
produces the expected results -- tried with Saxon 6.5.3, Xalan J 2.4.1,
MSXML4.
The result is:
<customerList>
<customer>
<field id="customerId">cust1</field>
<field id="customerName">Customer 1</field>
<fieldGroup id="homeAddress">
<fieldList>
<field id="street">98th Street </field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
<fieldGroup id="companyAddress">
<fieldList>
<field id="street">128th Street</field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
</customer>
</customerList>
The transformation processes "id" elements before any other elements and
does not depend on any order of the elements in the source xml document.
Which XSLT processor/version are you using?
Are you sure that you copied/pated well (exactly) the xslt code ?
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
"Sindigi, Ganesh K" <SindiGK(_at_)LOUISVILLE(_dot_)STORTEK(_dot_)COM> wrote
in message
news:0809DC8497D26748A7B1F36D36BC80A8AB3BD6(_at_)hqemailc(_dot_)louisville(_dot_)stortek(_dot_)com(_dot_)
..
Sorry I pasted the wrong error. I had put some comments in xsl
transformation. The error is coming at the line where an attribute is
created i.e., <xsl:attribute name="{name()}">. This time I used the
exact
transformation suggested by Dimitre. The output i got is below, only
change
is in line number.
<customerList>
<customer>
file:/C:/working/XML/posting/../elmToAtt.xsl; Line 59; Column -1; id
has
an
illegal attribute: {1}
<field id="customerId">cust1</field>
file:/C:/working/XML/posting/../elmToAtt.xsl; Line 59; Column -1; id
has
an
illegal attribute: {1}
<field id="customerName">Customer 1</field>
<fieldGroup id="homeAddress">
<fieldList>
<field id="street">98th Street </field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
<fieldGroup id="companyAddress">
<fieldList>
<field id="street">128th Street</field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
</customer>
</customerList>
-----Original Message-----
From: Sindigi, Ganesh K
Sent: Thursday, October 30, 2003 10:37 AM
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: RE: [xsl] Re: Converting specific child elements into attriutes
of parent
Thanks to all.
One thing I noticed is the order of elements in the source.xml is also a
reason for this error :-(
For e.g., if the <id> is coming after <value>, then this error is still
coming.
As the source xml is coming from different interfaces, i do not have any
control on the order of elements :-(. How do i resolve this?
When i ran the command "java org.apache.xalan.xslt.Process -in
source.xml
-xsl ..\elmToAtt.xsl"
Dimitre I used transformation provided by you and applied on this
source.xml.
(Notice that the order <id> and <value> elements in the first two
<field>s
has been interchanged)
<customerList>
<customer>
<field>
<value>cust1</value>
<id>customerId</id>
</field>
<field>
<value>Customer 1</value>
<id>customerName</id>
</field>
<fieldGroup>
<id>homeAddress</id>
<fieldList>
<field>
<id>street</id>
<value>98th Street </value>
</field>
<field>
<id>city</id>
<value>Chicago</value>
</field>
</fieldList>
</fieldGroup>
<fieldGroup>
<id>companyAddress</id>
<fieldList>
<field>
<id>street</id>
<value>128th Street</value>
</field>
<field>
<id>city</id>
<value>Chicago</value>
</field>
</fieldList>
</fieldGroup>
</customer>
</customerList>
which produced the following result (With two errors)
<customerList>
<customer>
file:/C:/working/XML/posting/../elmToAtt.xsl; Line 66; Column -1; id has
an
illegal attribute: {1}
<field id="customerId">cust1</field>
file:/C:/working/XML/posting/../elmToAtt.xsl; Line 66; Column -1; id has
an
illegal attribute: {1}
<field id="customerName">Customer 1</field>
<fieldGroup id="homeAddress">
<fieldList>
<field id="street">98th Street </field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
<fieldGroup id="companyAddress">
<fieldList>
<field id="street">128th Street</field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
</customer>
</customerList>
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)yahoo(_dot_)com]
Sent: Thursday, October 30, 2003 2:01 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Re: Converting specific child elements into attriutes of
parent
I have been trying to convert specific child elements into attributes
of
the
parent node. I looked through archive, there was a topic of
converting
all
children to attributes of the root. I followed the same thing and
tried
to
convert a specific child element, but i am getting following error.
elmToAtt.xsl; Line 18; Column -1; name() has an illegal attribute: {1}
I would like to copy the xml document and convert only specific
elements
into attributes.
I am not able to make out why this error is, but to no avail. Hoping
that
anybody in the list would help to resolve .
The specific error can be corrected by using AVT like this:
name="{name()}"
Here's a transformation, which converts any element, whose name is in a
list
of names, to an identically named attribute of its parent:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:my="my:my"
exclude-result-prefixes="my"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<my:elNames>
<name>id</name>
</my:elNames>
<xsl:variable name="elNames"
select="document('')/*/my:elNames/name"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:choose>
<xsl:when test="not(name() = $elNames)">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="*[name() = $elNames]"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="{name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="value">
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on your original source.xml:
<customerList>
<customer>
<field>
<id>customerId</id>
<value>cust1</value>
</field>
<field>
<id>customerName</id>
<value>Customer 1</value>
</field>
<fieldGroup>
<id>homeAddress</id>
<fieldList>
<field>
<id>street</id>
<value>98th Street </value>
</field>
<field>
<id>city</id>
<value>Chicago</value>
</field>
</fieldList>
</fieldGroup>
<fieldGroup>
<id>companyAddress</id>
<fieldList>
<field>
<id>street</id>
<value>128th Street</value>
</field>
<field>
<id>city</id>
<value>Chicago</value>
</field>
</fieldList>
</fieldGroup>
</customer>
</customerList>
the wanted result is produced:
<customerList>
<customer>
<field id="customerId">cust1</field>
<field id="customerName">Customer 1</field>
<fieldGroup id="homeAddress">
<fieldList>
<field id="street">98th Street </field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
<fieldGroup id="companyAddress">
<fieldList>
<field id="street">128th Street</field>
<field id="city">Chicago</field>
</fieldList>
</fieldGroup>
</customer>
</customerList>
Hope this helped.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list