I am creating the stylesheet for displaying info from fairly
large XML files (1 to 2 MB). The output is HTML and I'm using
the http://www.w3.org/1999/XSL/Transform namespace. I have to
alternate background colors of every row in a table. The FAQ
list has a straightforward answer that I've used:
<xsl:choose>
<xsl:when test="position() mod 2 = 0">
<xsl:attribute name="BGCOLOR">white</xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="BGCOLOR">gainsboro</xsl:attribute>
</xsl:otherwise>
</xsl:choose>
This should work, right? Wrong! The problem I have is that
I'm not selecting every element for the output tree.
This shouldn't matter. position() calculates the position of the current
node within the current node list, which is the list of nodes selected
using <xsl:apply-templates> or <xsl:for-each>. So long as you select the
nodes to be included using one of those instructions (and not, for
example, by selected a larger set of nodes and then selecting a subset
using xsl:if or xsl:choose) the position() should be set correctly.
For
instance, if I have five elements, and for some reason
(immaterial for the purpose of this question) I want to
select only elements 1, 3 and 5, they'll all end up being the
same color. My idea is that if I can store somehow the value
of the previous background, I can look at it
You can't store anything in XSLT - it's a side-effect-free language; and
there is no concept of "previous" - it's not a sequential execution
model.
Also, I have to display in the HTML document the name - only
once - of an element who has at least one descendant
satisfying certain conditions. The way I solved that was to
use xsl:for-each on the descendants, and select the name of
the element only on the first descendant satisfying the condition:
That shouldn't be necessary. I can't follow your code below but I think
you've made it much too difficult. From the description given above, you
should be doing something like:
<xsl:value-of select="name(element[.//*[conditions]][1])"/>
Michael Kay
<!-- Display the test name only if the test has numeric
results -->
<xsl:for-each
select="preceding-sibling::ResultList/Element/Numeric">
<!-- Display the test name only for the first
encountered numeric result (guarantees exactly one display of
the test name) -->
<xsl:if test="../preceding-sibling::Element/Numeric=false()">
<H2><br/><br/>
<FONT FACE="ARIAL">
<xsl:if test="../Status = ' Passed'">
<xsl:attribute
name="COLOR"><xsl:value-of
select="//ReportOptions/Colors/Passed"/></xsl:attribute>
<xsl:value-of
select="../../../Sequence"/>
<IMG
SRC="C:\TestStand\Examples\XMLReports\passed.gif"/>
</xsl:if>
<xsl:if test="../Status = ' Failed'">
<xsl:attribute
name="COLOR"><xsl:value-of
select="//ReportOptions/Colors/Failed"/></xsl:attribute>
<xsl:value-of
select="../../../Sequence"/>
<IMG
SRC="C:\TestStand\Examples\XMLReports\failed.gif"/>
</xsl:if>
</FONT>
</H2>
</xsl:if>
</xsl:for-each>
That worked just fine until somebody threw at me an XML file
that had some additional elements defeating the purpose my
checks to determine the "first" descendant. Again, if I would
have a way of knowing if the ancestor name has already been
displayed, I would be done. Wouldn't have to determine the
first descendant any more, just get a match on every
descendant but display only if the ancestor name hasn't been
displayed. Can this be done?
Thanks,
CV
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list