The XPath 2.0 functions and operators spec includes an algorithm to do
this as part of the definition of the deep-equal() function, and it's
fairly tortuous even using XPath 2.0 constructs. I would tackle it as a
grouping problem: take the union of the two sets of attributes, group
them on a compound key consisting of the attribute name and the
attribute value, and then check that each group has size 2.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Arvind Bassi
Sent: 29 October 2003 02:10
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How to compare the attributes of two elements
to ensure that they are equal
What is the best way to compare two elements in terms of
their attributes, and the attribute values? I need to ensure
that each element has the same number of attributes, the same
attribute names and the same attribute values.
I am currently working on a stylesheet which compares two xml
documents, and generates the differences between them. I have
used Lar Huttar's xml document comparison stylesheet as my
base (located at http://www.dpawson.co.uk), but am stuck on
augmenting it with checks on attributes.
I am currently stuck with something along the lines of:
...
<xsl:call-template name="compare-attributes">
with nodes as parameters
...
<xsl:template name="compare-attributes">
<xsl:param name="attrA"/>
<xsl:param name="attrB"/>
<xsl:for-each select="$attrA/@*">
.... check that the same attribute exists with
.... the same attribute exists
if it does then compare the values for equality
</xsl:for-each>
</xsl:template>
However, l cannot get a handle on each of the two attributes
to compare them. Can somebody help to fill in the blanks?
Thanks.
Arvind.
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