Thanks Michael
Case closed.
-----Original Message-----
From: Michael Kay [mailto:mhk(_at_)mhk(_dot_)me(_dot_)uk]
Sent: Dienstag, 28. Oktober 2003 11:18
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Do a copy of a document but avoid duplicates in
certain lists of tags
Sorry. This is painful. Let's spell it out.
If you declare a default namespace xmlns="some.uri" in a source XML
document, then an element written as <x> is actually <{some.uri}x>. That
is, its real name consists of both the namespace URI and the local name.
If you want to match such an element, you need to match both the uri and
the local name:
<xsl:template match="some:x" xmlns:some="some.uri">
It does not help to declare a default namespace in the stylesheet,
because the default namespace only applies to element names appearing
literally in the stylesheet (e.g. <x>), it does not apply to names used
within XPath expressions or match patterns.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Lenz, Georg
Sent: 28 October 2003 09:05
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: RE: [xsl] Do a copy of a document but avoid
duplicates in certain lists of tags
Hei Michael,
thanks for the advice.
I thought put everything in the default name space
and everything will workout.
But if I declare the default name space in the style sheet
it still does not work??
The style sheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns="http://www.w3.org/1999/xhtml";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:output method="xml" version="1.0" encoding="UTF-8"
indent="yes"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ul" >
<xsl:comment>From Here</xsl:comment>
<xsl:copy >
<xsl:for-each
select="li[not(.=following-sibling::li)]">
<xsl:copy>
<xsl:apply-templates
select="node()|@*"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
does not work on:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
<?xml-stylesheet type="text/xsl"
href="extractDublicates.xslt"?> <html
xmlns="http://www.w3.org/1999/xhtml";>
<head>
<title>Enter the title of your XHTML document
here</title>
</head>
<body>
<p>Enter the body text of your XHTML document here</p>
<div>
<p>Another chapter</p>
<ul>
<li>A</li>
<li>A</li>
<li>B</li>
<li>B</li>
<li>B</li>
<li>C</li>
<li>C</li>
</ul>
</div>
</body>
</html>
????
Georg Lenz
-----Original Message-----
From: Michael Kay [mailto:mhk(_at_)mhk(_dot_)me(_dot_)uk]
Sent: Dienstag, 28. Oktober 2003 09:18
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Do a copy of a document but avoid
duplicates in certain lists of tags
Precisely, as I suspected: you've put the elements in a
namespace and you therefore need to prefix their names in the
stylesheet.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf
Of
Lenz, Georg
Sent: 28 October 2003 06:44
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: RE: [xsl] Do a copy of a document but avoid
duplicates in certain lists of tags
Hei Michael,
its the default namespace, the document starts with
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
<?xml-stylesheet type="text/xsl"
href="extractDublicates.xslt"?> <html
xmlns="http://www.w3.org/1999/xhtml";>?
Georg Lenz
-----Original Message-----
From: Michael Kay [mailto:mhk(_at_)mhk(_dot_)me(_dot_)uk]
Sent: Montag, 27. Oktober 2003 18:57
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Do a copy of a document but avoid
duplicates in certain lists of tags
Probably the "ul" element is in the XHTML namespace. You need
to declare a prefix for this namespace in your stylesheet and
write match="xhtml:ul".
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf
Of
Lenz, Georg
Sent: 27 October 2003 16:15
To: 'XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: [xsl] Do a copy of a document but avoid duplicates
in certain lists of tags
I have the following problem:
I want a perfect copy of an xhtml document but want avoid coping
duplicates "li"s in all "ul" lists.
I tried:
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ul" >
<xsl:comment>From Here</xsl:comment>
<xsl:copy >
<xsl:for-each
select="li[not(.=following-sibling::li)]">
<xsl:copy>
<xsl:apply-templates
select="node()|@*"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
but it does not work.
It does not even touch the ul template?
If the document node would be "ul" it works???
Any help available.
Thanks in advance
Mit freundlichem Gruß / Best Regards
Georg Lenz
Java IDE Core
SAP AG
Neurottstrasse 16
69190 Walldorf
T +49-6227-7-64235
F +49-6227-7-74235
E georg(_dot_)lenz(_at_)sap(_dot_)com
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