Hi
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Whitney, Dan (CanWest Interactive)
Sent: Thursday, October 16, 2003 9:02 PM
To: 'mulberry - xsl'
Subject: [xsl] Question 2: consolidating footnotes/numbering
with same idref
(...)
Works great but want to consolidate the numbering for the
riref elements like so:
<table>
<tr>
<td>Row 1 - Column 1<sup>1</sup></td>
<td>Row 1 - Column 2</td>
<td>Row 1 - Column 3<sup>2</sup></td>
<td>Row 1 - Column 4</td>
<td>Row 2 - Column 1</td>
<td>Row 2 - Column 2<sup>3</sup></td>
<td>Row 2 - Column 3</td>
<td>Row 2 - Column 4<sup>1</sup></td>
</tr>
</table>
<table>
<tr>
<td>
<tr>
<td><b>1. </b>Footnote 1
</td>
</tr>
<tr>
<td><b>2. </b>Footnote 2
</td>
</tr>
<tr>
<td><b>3. </b>Footnote 3
</td>
</tr>
<!-- don't want this output
<tr>
<td><b>4. </b>Footnote 1
</td>
</tr>
</td>
</tr>
-->
</table>
Try this stylesheet:
<xsl:key match="RIREF" name="RIREF" use="@refid"/>
<xsl:template match="RS">
<table>
<tr>
<xsl:apply-templates select="RI"/>
</tr>
</table>
<table>
<xsl:apply-templates mode="footnote"
select="RI/RIREF[generate-id()=generate-id(key('RIREF',@refid)[1])]"/>
</table>
</xsl:template>
<xsl:template match="RI">
<td>
<xsl:apply-templates select="text()"/>
<xsl:apply-templates
select="../RI/RIREF[(_at_)refid=current()/RIREF/@refid][generate-id()=generat
e-id(key('RIREF',@refid)[1])]"/>
</td>
</xsl:template>
<xsl:template match="RIREF">
<sup>
<xsl:number count="RIREF" format="1" from="RS" level="any"/>
</sup>
</xsl:template>
<xsl:template match="RIREF" mode="footnote">
<tr>
<td>
<b>
<xsl:number count="RIREF" format="1. " from="RS" level="any"/>
</b>
<xsl:value-of select="."/>
</td>
</tr>
</xsl:template>
Regards,
Americo Albuquerque
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list