Will
<xsl:apply-templates select="row[(_at_)TemplateId!='TemplateRow']"/>
do it?
John Marshall
Accurate Software
80 Peach Street, Wokingham, Berkshire, RG40 1XH, UK.
Tel: +44 (0)118 977 3889
Fax: +44 (0)118 977 1260
http://www.accuratesoftware.com <http://www.accuratesoftware.com>
-----Original Message-----
From: Alan Flaherty [mailto:alan(_at_)thewebstudio(_dot_)co(_dot_)uk]
Sent: 08 October 2003 12:01
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] select nodes with an attribute not contained within an
excluding attribute
Hi List,
I have the following sample XML case:
<doc>
<paragraph id="Intro">
</paragraph>
<table>
<row>
<chunk id="HeaderText"/>
</row>
<row TemplateId="TemplatedRow">
Item1: <chunk id="Item1"/> Item2: <chunk id="Item2"/>
</row>
<row>
<chunk id="FooterText"/>
</row>
</table>
<paragraph TemplateId="Quotes">
<chunk id="QuoteHeader"/><newline/>
<chunk id="QuoteBody"/>
</paragraph>
<paragraph id="Finish">
</paragraph>
</doc>
I need to be able to *Any* elements with an Id attribute not contained
within *any* element with a TemplateId Attribute, templated items are
reported on separately.
The Idea is that the TemplateId'd elements are bound to a Data Source but
the others are not, at times it's easier to Load up the document and gather
all the non template bound Id's using the processing code just before I bind
the data to the documents rather than having to do this manually. There are
quite a few documents and this will make it all a little bit faster to do.
Regards,
Alan
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