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RE: XPath 2.0: Problems with the two boolean constants true and false

2003-10-06 07:49:15
To add to my previous reply, I should point out that Saxon should report
a type error on this stylesheet: you cannot pass an integer or string
value for a parameter whose required type is boolean.

Michael Kay

 
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com 
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
Dimitre Novatchev
Sent: 06 October 2003 11:15
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] XPath 2.0: Problems with the two boolean 
constants true and false 


 
 I see two problems with the boolean constants true and false:
 
   1. They cannot be used in an XPath expression -- cannot be
 distinguished from child::true and child::false

There are no constants "true" and "false". As in XPath 1.0, 
the truth 
values are represented by the function calls true() and false(). No 
change here from 1.0.
 
   2. boolean('false') is true.  This is especially confusing
 and may be the source of many programmers' headaches.

Again, no change here from 1.0. I haven't seen this cause 
much problem 
in practice, though the introduction of xs:boolean alongside 
[fn:]boolean may be confusing. xs:boolean() uses the schema 
rules: '0' 
and 'false' give false, '1' and 'true' give true, any other 
string is 
an error.
 
 Because of these I chose in my code to use functions
 returning xs:integer (0 and 1) and for templates to write 
 code like the following:
 
   <xsl:template name="And" 
match="*[namespace-uri()='allTrue-And']">
     <xsl:param name="arg1"/>
     <xsl:param name="arg2"/>
          <xsl:value-of select="number(number($arg1) and
 number($arg2))"/>
   </xsl:template>
 
 Am I wrong? Is there a way to overcome the above problems?
 

It seems odd to me to use numbers instead of booleans because you 
don't like the string-to-boolean conversions. If you don't like the 
string-to-boolean conversions just don't use them; you can 
still use 
booleans!

My confusion is due to the following:

This transformation:

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:f="http://fxsl.sf.net/";
xmlns:test="my:test"
  exclude-result-prefixes="f xs test"

  <xsl:output omit-xml-declaration="yes"/>
  
  <xsl:template match="/">
   <xsl:apply-templates select="document('')/*/test:*[1]">
     <xsl:with-param name="arg1" select="'false'"/>
     <xsl:with-param name="arg2" select="1"/>
   </xsl:apply-templates>
  </xsl:template>
  
  <test:test/>
  <xsl:template name="And" match="test:*">
    <xsl:param name="arg1" as="xs:boolean"/>
    <xsl:param name="arg2"  as="xs:boolean"/>
         <xsl:value-of 
         select="xs:boolean(xs:boolean($arg1) and 
xs:boolean($arg2))"/>
  </xsl:template>

</xsl:stylesheet>

Produces:

  true


But 

      <xsl:value-of 
         select="xs:boolean(xs:boolean('false') and xs:boolean(1))"/>

produces:

   false


Is this a bug in Saxon 7.7?






=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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