Hi
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Marsha Salo
Sent: Thursday, October 02, 2003 4:12 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Parameter problem
Hi Michael
Does $firstN have a value in the PartyList/When [1] template?
yes.
Is the PartyList/When [last()] template actually being called?
yes.
If so, something very odd is going on. Tell us which
processor you are
using, and post a complete stylesheet + source document so
we can debug
it for you.
I am using MSXML not sure about the processor. If i
have an xml parser do i automatically have a processor aswell?
I am using xmlSpy to step through the transformation
process. At the bottom of this mail is the html output i am getting.
The problem is not the param but where it is passed
On the <xsl:template match="PartyList"> template
You have <xsl:apply-templates select="When[(_at_)Attendance]">
This will select ALL <When> elements with a @Attendance attribute
In your <xsl:template match="PartyList/When[1]"> template you allso have
A <xsl:apply-templates select="following-sibling::When [last()]">
This will select the last following-sibling::When element
In the output you'll have:
When[1] - firstN set
When[last] - firstN set
When[...]
When[last] - firstN not set - this one is selected in the PartyList
template and, as sush, doesn't have the param set
You could set the parameter in the PartyList templates like:
<xsl:apply-templates select="When[(_at_)Attendance]">
<xsl:sort data-type="number" order="ascending"
select="@Attendance"/>
<xsl:with-param name="first" select="When[1]/@Attendance"/>
</xsl:apply-templates>
Or you can change the select so you only select the first When like:
<xsl:apply-templates select="When[(_at_)Attendance][1]">
<xsl:sort data-type="number" order="ascending"
select="@Attendance"/>
</xsl:apply-templates>
And let the When[1] template call the last one
Regards,
Americo Albuquerque
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