I must use Microsoft .NET parser and processor.
I need to fix a coathook but I must use a hammer...
Why?
Michael Kay
Postprocessing with multiple transformation, I think, is the
only viable solution. I hope there will be a serialization
capability defined for XSLT 2.0 .
Sergiu
Try saxon:serialize(), followed by one of the many ways of
doing string
replacement to double the quotes. Or you could write a
similar extension
function for a different processor. People have in the past
posted code
that does serialization in XSLT itself, and then uses
disable-output-escaping to prevent the markup being escaped, but I
wouldn't recommend it myself.
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf
Of
Sergiu Ignat
Sent: 30 September 2003 16:30
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Replace characters in a node and all of its
descendents
I need to generate an SQL "INSERT INTO" statement from an xml
document. One of the columns must hold the string
representation of an XML node with all of its descendents. To
insert this node as a string I must replace each single quote
with other two single quotes for conformance with SQL syntax.
I can not send a deep copy of the node taken with
<xsl:copy-of> to the $text parameter of the "replace-string"
template posted by Evan Lenz at
http://www.dpawson.co.uk/xsl/sect2/replace.htm> l
How can I get
a deep copy of a node as a string to process
it? Multiple transformations are not recomended. Thanks.
Sergiu Ignat
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