The filter step [last()] will be false for every node except the last.
So if your sequence is the current node list in a step then just adding
[last()] will do what you want.
If your sequence is the current node list in an xsl:for-each then use
<xsl:if test="position()=last()">....
Note that XPath1 does not have a sequence datatype node sets are sets so
inherently unordered so it don't really have a first or last node until
your sort the elements into document order (as happens in forward axes)
or reverse order (reverse axes) or with xsl:sort.
In xpath2 you can save a sequence in arbitrary order in a variable, then
$x[last()]
will give you the last in the sequence.
Where can I find a fast guide with all function's that can possible used in
xslt
apart from a few special functions (eg current() key() and documen())
all the functions are listed in teh Xpath spec at www.w3.org/tr/xpath
David
--
http://www.dcarlisle.demon.co.uk/matthew
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