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Re: XSL - using for-each with sort - can't access previous sorted nod e

2003-11-25 15:16:25
Jeff,

Make sure that when you sort you specify the data-type
<xsl:sort select="@page" data-type="number"/>
or the 18 will come after the 1 and before the 2.

rick

At 04:45 PM 11/25/2003 -0500, you wrote:
Hi all... just joined this list. Greetings :)

I was wondering if someone might have an answer for me on this...

Here's sample XML:

<quiz>
   <question id="1" page="4"/>
   <question id="2" page="6"/>
   <question id="3" page="1"/>
   <question id="4" page="18"/>
   <question id="5" page="7"/>
   <question id="6" page="5"/>
</quiz>

In my XSLT, I want to sort by page. So I have:

<xsl:for-each select="question">
<xsl:sort select="@page"/>

Now - as I am doing things to each question during the for-each, I want to
be able to access the "id" attribute in the question outputted JUST PRIOR to
the one currently being outputted. I can't seem to be able to do this. I've
tried using position() and <xsl:number> and combinations of the two, and
have been unsuccessful. Could anyone give me some advice?

Thanks,

Jeff


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Rick Taylor
XML Developer
PPDM Association


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