Hey,
I'm sorry for the unindented XML files in my last
email.
The following template can act like a filter since it
does nothing. The attribute "match" here indicate what
needs to be filtered out from the output.
<xsl:template match="*[preceding-sibling::Member[(_at_)name
='acc1']/Member[(_at_)name='acc11']]"/>
Here I wanted to remove(filter out) the element
Member(name attribute is "acc12") and its children
from the output. It is the sibling of the element
Member(name attribute is "acc11").
I assume that the "Member[(_at_)name = 'acc1']/Member[(_at_)name
= 'acc11']" is the path of Member("acc11"). However,
the match only recognized the "Member[(_at_)name ='acc1'].
So, the siblings of it got removed from the output,
which are the Member("acc2") and Member("acc3").
My question is, can we specify the path in the pattern
like I did in the above template? If I want to remove
the Member("acc12") that is the sibling of a Member,
how can I specify in the match pattern?
Thanks
Dongling
Hope this time my source XML is an indented one.
<D>
<Member comment="" name="acc1">
<Calc>+</Calc>
<Member comment="" name="acc11">
<Calc>+</Calc>
<Member name="account3_1"/></Member>
<Member comment="" name="acc12">
<Calc>+</Calc>
<Member name="acc121"/>
</Member>
</Member>
<Member comment="" name="acc2">
<Calc>+</Calc>
</Member>
<Member comment="" name="acc3">
<Calc>+</Calc>
<Member comment="" name="acc31">
<Calc>+</Calc>
</Member>
<Member comment="" name="acc32">
<Calc>+</Calc>
</Member>
</Member>
</D>
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
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