The problem is that the "<xsl:if test="position() mod
2 = 0"> won't work after a <xsl:sort> because the
position() function returns the position in the
original xml, not the in sorted nodes.
No, position() _never_ refers to a position in the original xml it
always refers to the current node list (which is sorted ion this case)
Just use position()
David
--
http://www.dcarlisle.demon.co.uk/matthew
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