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Re: Generating a 2 column table from only _some_ of the nodes.

2003-11-14 13:37:32
See:

   http://www.topxml.com/code/default.asp?p=3&id=v20020514091249

This snippet shows how to create from the nodes of an arbitrary node-set
(may not be siblings) a table withN columns, and alternating row colour.


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL


"Martin Buchan" <martinb(_at_)beam(_dot_)tv> wrote in message
news:3FB4BA8A(_dot_)8000101(_at_)beam(_dot_)tv(_dot_)(_dot_)(_dot_)
Hi,

Could anyone help me out with this. I have looked through the table
generation stuff on the site but I think my problem is slightly different.

I need to build a 2 column table from only some of the nodes in my node
set. Here is an excerpt from my XML.

<archive id="111111">
   <product label="Product" group="1. Product" required="t">aaa</product>
   <title label="Title" group="1. Product" required="t">bbb</title>
   <client label="Client" group="1. Product" required="t">ccc</client>
   <brand label="Brand" group="1. Product" required="t">ddd</brand>
   <jobref label="Job Reference" group="2. TV" required="f">eee</jobref>
   <tape_no label="Tape Number" group="2. TV" required="f">fff</tape_no>
   <duration label="Duration" group="2. TV" required="t">ggg</duration>
   <agency label="Agency" group="3. Agency" required="t">hhh</agency>
   <producer label="Producer" group="3. Agency" required="t">i</producer>
   <director label="Director" group="3. Agency" required="f">j</director>
</archive>

I dont know the element names in advance and I dont know how many
elements there will be. Also, I need to lay them out in groups. I.e. I
start a table for group "1. Product", lay out all the rows, finish the
table and start a new table for group "2. TV" etc.

I was doing this initially using a key to select all elements in a group
and the looping thru them with a for-each and using position() mod 2 = 1
and following-sibling::*[1] to lay out the first and second td.

This worked fine but now I need to only pick elements where @required =
'f'. This causes problems with following-sibling because there is no
gaurantee that the following-sibling will have @required = 'f'. I can
test for this but if it doesnt, then all i can do is layout an empty
cell - which I dont want. What I want is someway to move forward int eh
loop sort of.

Or, I want to build a new nodeset where @required = 'f'. I thought i was
doing this with a key which had @required = 'f' in the predicate but It
doesnt actually select only those nodes. It is selecing all the nodes.

Here is my key.

<xsl:key name="notreq1" match="/archive[1]/*[(_at_)required = 'f']"
use="@group" />

Here is my current for loop.

<xsl:for-each select="/archive/*[count(. | key('notreq1', @group)[1]) =
1]">

<xsl:if test="not(@required = 't'">
   <table width="100%" align="center" border="0">
     <tr><td>
       <xsl:value-of select="substring-after(../*[(_at_)group =
current()/@group]/@group, '. ')"/>
     </td></tr>
     <xsl:for-each select="key('notreq1', @group)[(_at_)required =
'f'][not(position() = 0)]">
       <xsl:sort select="@group" />
       <xsl:when test="(position() mod 2) = 1">
         <td><xsl:value-of select="."/></td>
           <xsl:choose>
             <xsl:when test="following-sibling::*[1]/@group = @group">
               <xsl:with-param name="content"
select="following-sibling::*[1]"/>
             </xsl:when>
             <xsl:otherwise>
               <td>EMPTY CELL</td>
             </xsl:otherwise>
           </xsl:choose>
         </xsl:if>
       </xsl:for-each>
     </xsl:if>
</xsl:for-each>


Can anyone see what I am trying to do?
Basically, my problem is with the node set i am looping through. Is
there some way I can loop through only nodes with @required = 'f'. I
thought the key did this. I.e. I thought I could build a new node set
with the key???

I will provide more info if needed. I am in very new territory here so
any help would be muchly appreciated.

Thanks

Martin



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