Following is the XSL code I am using...
I can't tell you what you should be doing (it's too late at night to try
and understand your problem clearly) but I can tell you a little about
what you're doing wrong.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<svg xmlns="http://www.w3.org/2000/svg";
xmlns:svg="http://www.w3c.org/2000/svg"; width="1656"
height="2088" viewBox="0 0 1656 2088">
<xsl:copy-of select="*[..]"/>
This xsl:copy-of instruction copies all children of the root node that
have a parent. Of course all children of the root have a parent, so the
predicate does nothing. If you left out the predicate, you would copy
the whole source document, without making any changes to it. That can't
really be what you want.
<xsl:for-each select="/">
This selects the root node of the tree and iterates over it. There's no
point in iterating over a node-set containing a single node (and it's
only selecting the node that's already the context node for this
template anyway).
<xsl:if test="position()=last()">
If you're iterating over one node, then that node will always be the
last...
<svg
xmlns="http://www.w3.org/2000/svg";
xmlns:svg="http://www.w3c.org/2000/svg"; x="456"
y="420" width="748" height="224">
Both these namespaces are already declared, why do you need to declare
them again?
<xsl:copy-of
select="document('http://10.96.10.20/servlet/ImageReaderByNIDQ
?nacid=119476&filetype=f')"/>
</svg>
<svg
xmlns="http://www.w3.org/2000/svg";
xmlns:svg="http://www.w3c.org/2000/svg"; x="396"
y="756" width="864" height="540">
<xsl:copy-of
select="document('http://10.96.10.20/servlet/ImageReaderByNIDQ
?nacid=119480&filetype=f')"/>
</svg>
</xsl:if>
</xsl:for-each>
</svg>
</xsl:template>
</xsl:stylesheet>
I'm sorry my comments aren't more constructive but I hope they help you
see what you're doing wrong.
Michael Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list