After you fix the fact that your file is not XML (bare ampersands are strictly
forbidden), this template will do what you want (on element "c9" at least. The
rest is left as an exercise for the reader.)
<xsl:template match="/dataroot/GrantNet/c9">
<xsl:variable name="year"><xsl:value-of select="substring-before(.,'-')"
/></xsl:variable>
<xsl:variable name="month"><xsl:value-of
select="substring(substring-after(.,'-'),1,2)" /></xsl:variable>
<xsl:variable name="day"><xsl:value-of
select="substring(substring-after(.,'-'),4,2)" /></xsl:variable>
<xsl:variable name="date"><xsl:value-of select="$month" />/<xsl:value-of
select="$day" />/<xsl:value-of select="$year" /></xsl:variable>
<xsl:value-of select="$date" />
</xsl:template>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: puja thakral <puja_thakral(_at_)yahoo(_dot_)com>
Sent: Tue, 4 Nov 2003 08:29:52 -0800 (PST)
To: List <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: [xsl] how to Display dates in a specific format
Hi All,
I've an xml document.
<?xml version="1.0" encoding="UTF-8"?>
<dataroot>
<GrantNet>
<c0>0005</c0>
<c1>111</c1>
<c2>GS</c2>
<fldSponsorDesc>American Association
</fldSponsorDesc>
<Program>2000-2001 American Fellowships</Program>
<URL>http://www.aauw.org/3000/fdnfelgra.html</URL>
<Description></Description>
<c9>1999-11-15T00:00:00</c9>
<c13>Web</c13>
<c14>1999-10-11T00:00:00</c14>
<c15>False</c15>
<c16>AH</c16>
<fldCatDesc>Arts & Humanities</fldCatDesc>
</GrantNet>
</dataroot>
I'm using stylesheet to display all the information in
html format.
But I don't know how to display date.I get the date
displayed as 1999-11-15T00:00:00 although I want to
display it as 11/15/1999.
Thanks for help in advance.
Regards,
Puja
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