What does count() =1 represent (got a bit confused about jeni's
explanation)
No, that's the wrong way round. The usual pattern is that I give the
confusing (or at least terse) explanation and Jeni explains it.
count(. | .....) =1
XSLT 1 does not have a test for node identity, you can use = to test if
one node has the same value as another but not whether it actually is
the same node.
You have an expression ...... (actually viewentry{key('ve-by-firstocc',
substring(entrydata[3]/text,1,1))[1]] ) that returns a node, and you
want to know if that node is the current node, not just if it has the
same character data, there are two methods to test that in xslt 1 (in
Xpath 2 you could just use
. is viewentry{key('ve-by-firstocc', substring(entrydata[3]/text,1,1))[1]] )
as the is operator tests node identity.
however in xslt 1 you use the set union method:
(. | .....)
is a set of nodes being the union of the current node (.) and the other
one (....) so either there is one node in this set (if . and ..... are
the same) or 2 nodes (if they are different) so testing count()=1
will determine this identity.
The other method (which is the one I tend to use as it's slightly
clearer I think) is to test
generate-id(.) = generate-id(.....)
as generate-id will return an id string taht is unique to each node, so
testing these strings will test identity.
note in the above "." means "." bit "...." is a meta placeholder for the
expression of interest (key('ve-by-firstocc',
substring(entrydata[3]/text,1,1))[1]]" in your case)
Just to be clear, am i right in saying that "viewentry{key('ve-by-firstocc',
substring(entrydata[3]/text,1,1))[1]]" selects the first of each group of
viewentries with the same key (including groups which only have one
viewentry in it)?
Yes.
David
--
http://www.dcarlisle.demon.co.uk/matthew
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