Hi Karthikeyan,
I guess, using the mathematical *mod operator* , to
calculate, the 10th, 20th .. rows, shall solve the
problem ,
The XSL fragment is --
<xsl:for-each select="TABLE/TBODY/ROW">
<tr>
<td>
<xsl:value-of select="ENTRY[1]/PARA[1]"/>
</td>
<td>
<xsl:value-of select="ENTRY[2]/PARA[2]"/>
</td>
</tr>
<xsl:if test="position() mod 10 = 0">
<tr>
<td>=============================
</td>
<td>============================
</td>
</tr>
</xsl:if>
</xsl:for-each>
Regards,
Mukul
--- "karthikeyan.balasubramanian"
<karthikeyan(_dot_)balasubramanian(_at_)aspiresys(_dot_)com> wrote:
Hi,
I am not sure if I have put correct subject.
I want to display 10 records in a table
after this I want to show horizontal line and
display another 10 and this sequence
continues. How do I keep track of this
information?
Output
=====
heading : data1
data1, data2, data3, data4, data5
data6, data7, data8, data9, data10
============================
heading: data11
data11, data12, data13, data14, data15
data16, data17, data18, data19, data20
============================
heres my xsl
============
<xsl:template match="NI">
<h1>heading : ?</h1>
<table>
<tr>
<td>sub-title1</td>
<td>sub-title2</td>
</tr>
<xsl:for-each select="TABLE/TBODY/ROW">
<tr>
<td>
<xsl:value-of select="ENTRY[1]/PARA[1]"/>
</td>
<td>
<xsl:value-of select="ENTRY[2]/PARA[2]"/>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
sample xml
===========
<NI PUBLISH="DEC31">
<TABLE>
<TBODY>
<ROW>
<ENTRY>
<PARA>MS9557-09</PARA>
<PARA LEVEL="2">73 34 15 01 010</PARA>
</ENTRY>
<ENTRY>
<PARA/>
<PARA>3</PARA>
</ENTRY>
</ROW>
<ROW>
<ENTRY>
<PARA>MS9557-09</PARA>
<PARA LEVEL="2">73 34 15 01 010</PARA>
</ENTRY>
<ENTRY>
<PARA/>
<PARA>3</PARA>
</ENTRY>
</ROW>
</TBODY>
</TABLE>
</NI>
Have a great day.
Karthikeyan B
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