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Re: Embedded xsl:for-each

2003-12-30 07:17:51
Hi,

Have managed to figure out what I am doing wrong.  Thanks and sorry to be a
pain.

Regards

Mark

----- Original Message -----
From: "Mark Williams" <mark(_at_)skwirel(_dot_)com>
To: "XSL-List" <XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Tuesday, December 30, 2003 1:39 PM
Subject: [xsl] Embedded xsl:for-each


Hi,

I'm trying to embed for-each statements within each other, but I am having
problems.  Take as an example the following XML file

<root>
<data>
<Table1>
<SUM>123.00</SUM>
<Table2>
<TablePolicy_No>123456</TablePolicy_No>
<TablePolicy_No>789101112</TablePolicy_No>
</Table2>
</Table1>
<Table1>
<SUM>12.25</SUM>
<Table2>
<TablePolicy_No>12</TablePolicy_No>
<TablePolicy_No>789</TablePolicy_No>
</Table2>
</Table1>
</data>
</root>


and the following excerpt from a fo file:

<xsl:for-each select="data/Table1">

<xsl:for-each select="Table2">

<fo:block font-family="Times-Roman" font-size="12pt" text-align="justify"
space-after="0.05pt">

<xsl:if test="position() = 1">Sum value = <xsl:value-of
select="SUM"/></xsl:if>

Policy No= <xsl:value-of select="TablePolicy_No"/>

</fo:block>

</xsl:for-each>

</xsl:for-each>



I was expecting this to produce the following:



Sum value = 123.00 Policy No = 123456

Policy No = 789101112

Sum value = 12.25 Policy No = 12

Policy No = 789



Instead it is producing

Sum value = Policy No =123456

Sum Value = 12.25 Policy No = 12



I can understand why the sum value is not generated as it is looking for
SUM
as a child of Table2 when in fact it is a child of Table1.  How do I
obtain
the value of SUM in this situation.



I don't understand why I am only getting 1 policy no value for each
repetition of Table1 with its nested repetition of Table2.



Any help would be appreciated.


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