Thanks guys.
Mark
----- Original Message -----
From: "Thomas Rasmussen" <tbr77(_at_)post(_dot_)tele(_dot_)dk>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Monday, December 29, 2003 6:33 PM
Subject: Re: [xsl] Re for-each identifying current iteration
Mark Williams wrote:
Hi,
I'm sure there is an incredibly easy way of doing this, but as usual I
can't
find it!
During a for-each iteration how do you identify what is the integer value
of
the current iteration.
Thanks
Mark Williams
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Hello
I think position() could do the job:
#xsl
<xsl:template match="/">
<xsl:for-each select="/root/node">
<xsl:value-of select="position()"/>
</xsl:for-each>
</xsl:template>
# xml-file
<root>
<node/>
<node/>
</root>
Regards
ThomasRasmussen
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list