This solution is more succinct and it works in the sablotron
configuration I have currently. I see why the parenthesis are necessary,
to keep referencing the movie nodes at a global level.
Thank you for your help!
Cynthia
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)yahoo(_dot_)com]
Sent: Tuesday, December 23, 2003 3:02 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Re: Finding position of a node relative to the root
instead of the parent node
Your problem is that in your code you have expressions like this:
//movie[position() <= number($thisMany)]
When actually you want this expression instead:
(//movie)[position() <= number($thisMany)]
Investigate this problem (e.g. look into the XSL FAQ) and try to
understand the difference between the two XPath expressions. This is a
FAQ about using the abbreviation //
So, you have to make just two changes in your code:
1. Change:
<xsl:for-each select="//movie[position() <=
number($thisMany)]">
to:
<xsl:for-each select="(//movie) [position() <=
number($thisMany)]">
2. Change:
<xsl:for-each select="//*[name()='movie'][position() >
number($thisMany)]">
to:
<xsl:for-each select="(//*[name()='movie']) [position() >
number($thisMany)]">
The corrected code now produces a nice 2-column table.
Dimitre Novatchev.
FXSL developer
http://fxsl.sourceforge.net/ -- the home of FXSL
Resume: http://fxsl.sf.net/DNovatchev/Resume/Res.html
"Cynthia DeLaria" <cdelaria(_at_)quris(_dot_)com> wrote in message
news:CE54CE22EF3A65438885197A240E408BC5772D(_at_)mx1(_dot_)hq(_dot_)quris(_dot_)com(_dot_)(_dot_)(_dot_)
Good Day,
I have searched the xsl list unsuccessfully for an answer to this
question, although I'm sure something like this has been addressed. I
think I'm just not sure what to search on to find it.
I have the following xml snippet:
<nr>
<featured>
<movie title="Charlie's Angles: Full
Throttle">Description</movie>
<movie title="28 Days Later">Description</movie>
<movie title="The Santa Clause 2">Description</movie>
</featured>
<also_new>
<movie title="Northfork" />
<movie title="Rudy: The Rudy Giuliani Story" />
<movie title="Russian Ark" />
</also_new>
</nr>
Basically, in the fully-flushed out version of the XML, the <featured>
movies have images and full descriptions, while the <also_new> movies
have only a title and rating. What I need to do is find a way to find
the position of each <movie> node relative to the root, as I need to
create a "print the new releases" page that lists all new releases in
two columns. This is what I tried, but it gives me the position based
on the parent (i.e. <also_new> or <featured>) not relative to the
root.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" encoding="ISO-8859-1" /> <xsl:template
match="/nr"> <html>
<head>
<title>New Releases E-Newsletter</title>
<head>
<body bgcolor="#ffffff" text="#000000" link="#023f7e" alink="#ff0000"
vlink="#023f7e">
Just print out this list.<br />
<table width="100%">
<xsl:variable name="thisMany"><xsl:value-of
select="(count(//*[name()='movie']) div 2)" /></xsl:variable>
<tr>
<td valign="top" width="50%" class="body2">
<br />
<xsl:for-each select="//movie[position() <=
number($thisMany)]">
<b><i><xsl:value-of select="./@title" /></i></b><br />
</xsl:for-each>
<br />
</td>
<td valign="top" width="50%" class="body2">
<br />
<xsl:for-each select="//*[name()='movie'][position() >
number($thisMany)]">
<b><i><xsl:value-of select="./@title" /></i></b><br />
</xsl:for-each>
<br />
</td>
</tr>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Is it possible to get the position relative to the root node? It seems
like this should be very simple, but all of the things I have tried
have not worked to produce the intended outcome.
Thank you!
Cynthia
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list