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Re: Transfer a subelement to top

2003-12-14 01:03:56
Hi Marc,

The following XSL shall work ;)

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>

<xsl:template match="/p">
  <xsl:apply-templates/>
</xsl:template>
        
<xsl:template match="text()">
  <p>
   <xsl:copy-of select="."/>
  </p>
</xsl:template>
        
<xsl:template match="table">
  <xsl:copy-of select="."/>
</xsl:template>
        
</xsl:stylesheet>

The XML, to which I applied the XSL is --
<?xml version="1.0" encoding="UTF-8"?>
<p>
  some text 1
  <table>
   abc
  </table>
  some text 2
</p>

The o/p is --
<?xml version="1.0" encoding="UTF-8"?>
<p>
  some text 1
</p>
<table>
  abc
</table>
<p>
  some text 2
</p>

Regards,
Mukul

--- Marc Tricou <MarcTricou(_at_)gmx(_dot_)de> wrote:
Hi,

I have an HTML structure like this:

<p>
    some text
    <table>
     ...
    </table>
    some text
</p>

How can i cut the embedding <p>-Tag into three
parts, before and after the
table tag, so that i get this:

<p>
  some text
</p>
<table>
...
</table>
<p>
  some text
</p>


It would also be ok, if the table tag is embedded by
<p>.  In an imperative
language i would know the way to go, but how to do
it in XSL?

Regards,
Marc

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