That doesn't work since the context node isn't the node for the for-each.
This is the complete for-each:
<xsl:for-each select="ROW[count(. | key('tipos', D)[1]) = 1]">
a_valores[<xsl:value-of select="position()-1" />] = new Array(<xsl:value-of
select="count(. | key('tipos', A)[1])" />);
a_valores[<xsl:value-of select="position()-1" />][<xsl:value-of
select="count(. | key('tipos', D))-1" />] = new Array(2);
a_valores[<xsl:value-of select="position()-1" />][<xsl:value-of
select="count(. | key('tipos', D))-1" />][0] = <xsl:value-of select="D" />;
a_valores[<xsl:value-of select="position()-1" />][<xsl:value-of
select="count(. | key('tipos', D))-1" />][1] = <xsl:value-of select="D" />;
</xsl:for-each>
This follows the muenchian grouping algorithm. In that case position() gets the
parent of ROW since the template is:
<xsl:template match="ficha_tecnica/ROWSET">
The way I have now is by using count(. | key('tipos', D)) and it works, but I
think that if I have more data, that process will be inefficient since it has
to count the actual nodes for each iteration.
My for-each gets the following:
a_valores[0] = new Array(1);
a_valores[0][0] = new Array(2);
a_valores[0][0][0] = .30726074;
a_valores[0][0][1] = .30726074;
a_valores[1] = new Array(1);
a_valores[1][0] = new Array(2);
a_valores[1][0][0] = .12244368;
a_valores[1][0][1] = .12244368;
a_valores[2] = new Array(1);
a_valores[2][0] = new Array(2);
a_valores[2][0][0] = .4071683;
a_valores[2][0][1] = .4071683;
Jaime
-----Mensaje original-----
De: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]En nombre de
David
Carlisle
Enviado el: Jueves, 11 de Diciembre de 2003 12:32
Para: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Asunto: Re: [xsl] getting the counter for a for-each statement
this has already been answered today in a differentthread.
<xsl:value-of select="position()"/>
--
http://www.dcarlisle.demon.co.uk/matthew
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