Re: Question about generating a full tree from a tree with xrefs using x

I'll assume a wrapper element x so your input is well formed

<x>
<elem id="a1" type="w">
  <text>aa</text>
</elem>
<elem id="a2" type="x">
  <text>bb</text>
  <ref>a1</ref>
</elem>
<elem id="a3" type="y">
 <text>cc</text>
  <ref>a2</ref>
</elem>
<elem id="a4" type="x">
 <text>dd</text>
  <ref>a1</ref>
</elem>
</x>



<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
<xsl:output method="text"/>

<xsl:key name="ref" match="elem" use="ref"/>

<xsl:template match="x">
<xsl:apply-templates select="elem[(_at_)type='w']"/>
</xsl:template>

<xsl:template match="elem[(_at_)type='w']">
process node <xsl:value-of select="@id"/> with text <xsl:value-of 
select="text"/> 
<xsl:apply-templates select="key('ref',@id)[(_at_)type='x']"/>
</xsl:template>

<xsl:template match="elem[(_at_)type='x']">
  process node <xsl:value-of select="@id"/> with text <xsl:value-of 
select="text"/> 
<xsl:apply-templates select="key('ref',@id)[(_at_)type='y']"/>
</xsl:template>

<xsl:template match="elem[(_at_)type='y']">
    process node <xsl:value-of select="@id"/> with text <xsl:value-of 
select="text"/> 
<xsl:apply-templates select="key('ref',@id)[(_at_)type='z']"/>
</xsl:template>

<xsl:template match="elem[(_at_)type='z']">
 none of these should be there
</xsl:template>


</xsl:stylesheet>


$ saxon tree.xml tree.xsl

process node a1 with text aa
  process node a2 with text bb
    process node a3 with text cc
  process node a4 with text dd


Note the above stylesheet is enforcing that it only looks for elements
of a specified type at each level. If you know that only type y eleemnts
are going to refer to type x elements then you could compress all these
templates down to just one.

David


-- 
http://www.dcarlisle.demon.co.uk/matthew

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