Thanks very much.
This was actually the basis for producing pages of content in HTML.
I had a list of elements and I needed to render eight elements per page.
I would have used a simple <xsl:for-each...> construct but I was in the
middle of an HTML page.
I converted the html page to a template and passed it a section of the
tree to render, consisting of a part tree collected by a similar process
as described below.
Thanks for your help
Paul
PB
On Tue, 2003-12-09 at 15:26, Mukul Gandhi wrote:
Hi Paul,
I have written the following XSL, to illustrate the
concept.. I guess, you wish to access the 11th node ;)
XSL
---
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="root">
<xsl:for-each select="child">
<xsl:if test="position() = 11">
<xsl:call-template name="print11thNode">
<xsl:with-param name="x" select="."/>
</xsl:call-template>
</xsl:if>
</xsl:for-each>
</xsl:template>
<xsl:template name="print11thNode">
<xsl:param name="x"/>
<xsl:value-of select="$x"/>
</xsl:template>
</xsl:stylesheet>
The XML, I have assumed is --
<?xml version="1.0" encoding="UTF-8"?>
<root>
<child>1</child>
<child>2</child>
<child>3</child>
<child>4</child>
<child>5</child>
<child>6</child>
<child>7</child>
<child>8</child>
<child>9</child>
<child>10</child>
<child>11</child>
<child>12</child>
<child>13</child>
<child>14</child>
<child>15</child>
</root>
I have added the numbers 1,2,3 etc, within child tags,
for illustration purpose ;)
I hope, my answer is useful ;)
Regards,
Mukul
--- Paul Barclay <paul(_dot_)barclay(_at_)digitalbridges(_dot_)com>
wrote:
Given the XML.
<root>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
<child ..../>
</root>
what is the XSL expression to select the 3rd to the
8th child of root?
Thanks
Paul
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