Hello,
I was able to find the solution to my problem:
<xsl:template match="class[class]">
<xsl:apply-templates select="class"/>
</xsl:template>
<xsl:template match="class">
<xsl:element name="option">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
I did not know you could use a select attribute when applying templates. But
this leaves me with a question: If I left "select" out of the
apply-templates xsl element, I would have thought it would only apply the
templates that I defined. Does the processor output all nodes anyway? In
other words, if I put in an "apply-templates" element, and I have no
templates defined for a particular node (or set?), why do I get output?
I think this is where my confusion lies, and isn't really explained in
simple terms anywhere I have looked.
Regards,
/johnny :)
On 1/12/03 9:59 PM, "JCS" <subscriber(_at_)pezagency(_dot_)com> wrote:
Hello,
I'm new to XSL/T and I've been reading the list archives, the tutorials
available in and around the net, etc., but I can't seem to find an answer to
a simple question (which is usually the case with simple "abstract"
questions) so I hope nobody minds if I ask here.
I've got an XML structure as so:
<name></name>
<name></name>
<name>
<name></name>
<list>
<item></item>
<list>
</name>
<name></name>
Now, I've been able to get at what I want using the examples provided by
this list, so I'm not having difficulty with the more intermediate steps,
however, I'm having difficulty getting my head this:
What if I just want to select the <name> node? If I use
<xsl:apply-templates/> and select "name" I get all name elements, plus the
item element which I don't want. I just want a list of names from the name
elements.
Do I have to specify a template for each element in an XML document? That
seems rather tedious, especially if I have a lot of elements within <name>
elements used as containers.
Any help is appreciated,
TiA,
/johnny :)
--
"You cannot discover new oceans unless you have the courage to lose sight
of the shore."
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