Use the position() function http://www.dpawson.co.uk/xsl/sect2/N6099.html.
Cheers Agnes
-----Original Message-----
From: Christian Beutenmueller
[mailto:beutenmueller(_at_)ebus(_dot_)informatik(_dot_)uni-leipzig(_dot_)de]
Sent: maandag 26 januari 2004 16:05
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] nearly FAQ .. (numbering of elements)
Hi,
I know, that this question is nearly a faq, and I know that it should be
possible to solve that problem, using the answers in the archive .. but
it seems that I am to stupid (and not really a good funtional programmer).
Ok here is my Problem:
I have an xml file, which looks like that:
<my-foo>
<text1></text1>
<question>[..]</question>
<question>[..]</question>
</my-foo>
Now I need in my output (an xsl:fo with some special extensions)
something like:
Q1 [..]
Q2 [..]
for the question tags.
The xslt transformation, I used until now is very simple:
One template for every node that can come after the root node, and a
final <xsl:template match="/"> that outputs some static stuff (the page
master for the xsl:fo), and then a simple: <xsl:apply-templates />
This simple design works perfect for this little transformation, but I
don't know how to implement the numbering.
Thanks in advance
Christian
--
"A truly outstanding programmer can find bugs
buried in a 6 megabyte core dump without using a hex calculator"
[http://www.pbm.com/~lindahl/real.programmers.html]
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