Hi Bert,
<xsl:for-each select="root/person[gender = 'male' and age='41']">
Best Regards,
George
-------------------------------------------------------
George Cristian Bina mailto:george(_at_)oxygenxml(_dot_)com
<oXygen/> XML Editor - http://www.oxygenxml.com/
----- Original Message -----
From: "Bert" <arm(_at_)xs4all(_dot_)nl>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, January 22, 2004 9:21 PM
Subject: [xsl] Question about "for-each select"
Hi,
I need some help/advice on the following subject.
From the xml-file below I want to get the information of all the males
who
are 41.
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="persons.xsl"?>
<root>
<person>
<name>Bert</name>
<gender>male</gender>
<age>41</age>
</person>
<person>
<name>Elisa</name>
<gender>female</gender>
<age>41</age>
</person>
<person>
<name>Carl</name>
<gender>male</gender>
<age>40</age>
</person>
</root>
I use the following template to do that (at least I try to do that):
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="no"/>
<xsl:template match="/">
<document>
<xsl:for-each select="root/person[gender = 'male']">
<xsl:sort select="name" order="ascending"/>
<xsl:value-of select="name"/>
<xsl:value-of select="' - '"/>
<xsl:value-of select="age"/>
<br/>
</xsl:for-each>
</document>
</xsl:template>
</xsl:stylesheet>
Actually I need a 'for-each'-statement like this:
<xsl:for-each select="root/person[gender = 'male']" AND "root/person[age =
'41']">
This obviously doesn't work. Can it be done this way and if not, how can I
achieve my goal?
As you can see help is welcome!
Kind regards,
Bert
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list