At 2004-01-19 15:24 +0100, SHEIKH Sajjad wrote:
In the following xml document, what is the best way to display 'id' and
'description' of element lln and 'name' of element N when
objname='Folder'?
Do you mean the way to address it in XPath? One way would be to set the
context using for-each and then pick and choose what you need.
If you had prefixed text:
<xsl:for-each select="lln[(_at_)objname='Folder']">
<!--prefix stuff-->
<xsl:value-of select="@id"/>
<!--infix stuff-->
<xsl:value-of select="@description"/>
<!--infix stuff-->
<xsl:value-of select="n/@name"/>
<!--suffix stuff-->
</xsl:for-each>
If you just wanted them grouped together, you could concatenate them with
spaces (or not):
<xsl:for-each select="lln[(_at_)objname='Folder']">
<xsl:value-of select="concat( @id, ' ', @description, ' ', n/@name )"/>
</xsl:for-each>
If you want to create an importable fragment with which you can specialize
the processing of each of the elements by an importing stylesheet with
overriding template rules:
<xsl:for-each select="lln[(_at_)objname='Folder']">
<!--prefix stuff-->
<xsl:apply-templates select="@id"/>
<!--infix stuff-->
<xsl:apply-templates select="@description"/>
<!--infix stuff-->
<xsl:apply-templates select="n/@name"/>
<!--suffix stuff-->
</xsl:for-each>
Do you mean the way to display it in appearance? I like blue, myself.
I hope this helps!
........................ Ken
<ll>
<lln id="123" objname="Folder" description="a folder" name="lln one
name">
<n name="n one name"/>
</lln>
<lln id="131" objname="Folder" description="a folder1" name="lln one
name1">
<n name="n one name1"/>
</lln>
<lln id="143" objname="Document" description="a folder2" name="lln one
name2">
<n name="n one name2"/>
</lln>
</ll>
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