I would suggest:
<xsl:variable name="index">
<foobar>http:......</foobar>
<jaka>http:....</jaka>
</xsl:variable>
<xsl:variable name="nsindex" select="xx:node-set($index)/*"/>
<xsl:template match="category">
<xsl:variable name="catname" select="name" />
<xsl:for-each
select="document($nsindex/*[name()=$catname])/root/child::*)">
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
james walker
Sent: 12 January 2004 16:15
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] referring to variables using variables?
Is there anyway that i can achieve the same solution but in a
slightly
different way?
thanks james walker
From: "Michael Kay" <mhk(_at_)mhk(_dot_)me(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: RE: [xsl] referring to variables using variables?
Date: Mon, 12 Jan 2004 15:51:08 -0000
XSLT is not a macro language. The content of a variable is a value
(either a boolean, a string, a number, or a node-set). It is
not part
of the text of an XPath expression. I think this is where your
confusion comes from.
For example, if $x contains the string 'xyz', then $x/pqr
does not mean
xyz/pqr, it means 'xyz'/pqr, which is an error: the operands
of the "/"
operator must be node-sets, not strings.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf
Of james
walker
Sent: 12 January 2004 13:56
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] referring to variables using variables?
I am trying to access different xml documents where the variable
name of the document (declared at the top of the file) is
equal to
the category name of
the file being translated:
e.g. given this xslt:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:variable name="jaka" select="document('http:......')" />
<xsl:variable name="foobar" select="document('http:......')" />
<xsl:template match="category">
<xsl:variable name="catname" select="name" />
<xsl:for-each select="$catname/root/child::*)"> <li><xsl:value-of
select="detail" /></li> </xsl:for-each> <xsl:apply-templates
select="./category" /> </xsl:template> </xsl:stylesheet>
I translated this with file1.xml which contained the two category
names jaka aand foobar. i have named the categories in
the file1.xml
to be $foobar and
$jaka so when $catname is substitued into
$catname/root/child::* it should
look like $foobar/root/child::* for foobar categoyr and
$jaka/root/child::*
for jaka category.
However, when i translate it, it doesnt seem to show
anything when
it gets to the xpath staement $catname/root/child::*.
I tested to see if it works when u put the variable name
directly in there
and it does (e.g. putting $foobar/root/child::* )??
Does anyone know if i am close to the solution (am i making a
silly mistake
with variable decalration?0
cheers
james walker
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