you can add the condition as a predicate in the forloop and get rid of the
if condition inside the for loop. this will avoid looping through the nodes
that you dont want as opposed to getting in and checking for the condition..
like
<xsl:for-each select="Item/Field[generate-id(Value) = generate-id(key('x',
Value)[1])]">
just a cursory glance at it....
vasu
----- Original Message -----
From: "Mukul Gandhi" <mukulgandhi2003(_at_)yahoo(_dot_)co(_dot_)in>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, January 08, 2004 12:54 PM
Subject: Re: [xsl] Obtaining a list of unique values
Hi Sasa,
Please try the XSL --
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:key name="x" match="Value" use="." />
<xsl:template match="/root">
<xsl:for-each select="Item/Field">
<xsl:if test="generate-id(Value) =
generate-id(key('x', Value)[1])">
<xsl:value-of select="Value" />
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
The XSL above, uses Muenchian method for Grouping.
Regards,
Mukul
--- Sasa Cekrlija <sasa(_dot_)cekrlija(_at_)mks(_dot_)com> wrote: >
Given an XML file that contains a list of Items each
having an attribute
Colour with its value,
is it possible to obtain a list of all unique
colours of Items.
For example if XML looks something like this:
<Item name="item1">
<Field name="Colour">
<Value>Red</Value>
</Field>
</Item>
<Item name="item2">
<Field name="Colour">
<Value>Blue</Value>
</Field>
</Item>
<Item name="item3">
<Field name="Colour">
<Value>Red</Value>
</Field>
</Item>
Then I would like to obtain a list containg exactly
two entries: Red, Blue
Thanks!
Sasa C.
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