Sorting results by output of a conversion template

Hi,

I have some sophisticated sorting to do and only a basic level of
knowledge.

Essentially, I have an element coming down called 'assignStartTime' which
holds a three-digit numeric value e.g. 181, 145, 85, 133 etc etc. Now,
these figures actually represent a time and once passed through to a
conversion template (called 'convertApptEndTime'), return a figure like
12:00pm or 3:00pm etc etc. The conversion template looks like this:

<xsl:template name="convertApptStartTime">
      <xsl:param name="node"/>

      <xsl:variable name="hour" select="number(floor((($node - 1)*5) div
60))"/>

      <!-- get transformed start time value -->
      <xsl:call-template name="convertApptStartTimeShort">
         <xsl:with-param name="node" select="$node"/>
      </xsl:call-template>

      <xsl:choose>
            <xsl:when test="$hour &gt;= 12">
                  <xsl:text>pm</xsl:text>
            </xsl:when>
            <xsl:otherwise>
                  <xsl:text>am</xsl:text>
            </xsl:otherwise>
      </xsl:choose>
</xsl:template>

<xsl:template name="convertApptStartTimeShort">
      <xsl:param name="node"/>

      <xsl:variable name="hour" select="number(floor((($node - 1)*5) div
60))"/>
      <xsl:variable name="minute" select="number((($node - 1)*5) mod 60)"/>

      <xsl:choose>
            <xsl:when test="$hour &gt; 12">
                  <xsl:if test="$minute &gt; 9">
                        <xsl:value-of select="number($hour -
12)"/>:<xsl:value-of select="$minute"/>
                  </xsl:if>
                  <xsl:if test="$minute &lt; 10">
                        <xsl:value-of select="number($hour -
12)"/>:0<xsl:value-of select="$minute"/>
                  </xsl:if>
            </xsl:when>
            <xsl:otherwise>
                  <xsl:if test="$minute &gt; 9">
                        <xsl:value-of select="$hour"/>:<xsl:value-of select
="$minute"/>
                  </xsl:if>
                  <xsl:if test="$minute &lt; 10">
                        <xsl:value-of select="$hour"/>:0<xsl:value-of
select="$minute"/>
                  </xsl:if>
            </xsl:otherwise>
      </xsl:choose>
</xsl:template>


I need to be able to sort my results by the output of this template.
So...is there a way using XSL:SORT to call a template (like the one above)
and sort the results that way?? e.g. I'm using xsl:for-each to run through
my XML elements and call a tableRow template which produces the HTML..
Somehow, I'd like to sort via time as noted in bold in the xsl:sort
statement below.


<xsl:for-each select="startTime">

      <xsl:sort select="OUTPUT-FROM-MY-CONVERSION-TEMPLATE"/>

      <xsl:call-template name="tableRow">
            <xsl:with-param name="pColour" select="'#EEEEFF'"/>
      </xsl:call-template>

</xsl:for-each>


I don't know if it's possible or not but many thanks for your time.

Regards
Allan







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