My XSLT code has a template into which I pass the two
nodes in $newNode and $oldNode but I'm getting compilation
errors. I know the following code is wrong but hopefully
it'll be obvious what I'm trying to accomplish with it:
<xsl:for-each select="$newNode/@*">
<xsl:if test="string(current()) = $oldNode/@{name()}">
XPath expressions *never* contain curly braces. They are only used to
surround an XPath expression that is embedded in an ordinary attribute
value.
You want
test=". = $oldNode/@*[name()=name(current())]"
Michael Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list