At 2004-01-05 10:51 -0500, Norma Yeazell wrote:
I have two seqlist lists in a row in my xml like:
<seqlist>
<item>this is item 1</item>
<item>this is item 2</item>
<item>this is item 3</item>
</seqlist>
<seqlist>
<item>this is item 1</item>
<item>this is item 2</item>
<item>this is item 3</item>
</seqlist>
Again, you are trying to infer a hierarchy where none exists.
I can get it to number them but I need the second list to be numbered
starting with the last item from the first list.
I've tried <xsl:number count="item" level="multiple" format="1.1.1"/>
That relies on hierarchy in your input and one isn't there.
The outcome should look like.
1. this is item 1
2. this is item 2
3. this is item 3
3.1. this is item 1
3.2. this is item 2
3.3. this is item 3
When doing the second <seqlist>, count the members in the first. To
generalize it, you will probably need to do something along the lines of
the following from within an item:
<xsl:for-each select="../preceding-sibling::seqlist">
<xsl:value-of select="count(item)"/>.<xsl:text/>
</xsl:for-each>
<xsl:number/>. <xsl:text/>
The above should give you the following in the third <seqlist> list:
3.3.1 this is item 1
I hope this helps.
................... Ken
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