Given a input xml of
<input>
<data>...</data>
<table>...</table>
</input>
Will this do what you want? It's probably not the most efficent since I'm
doing n*n for-each loops... :(
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/>
<xsl:template match="/">
<data>
<xsl:apply-templates select="./input/data"/>
</data>
</xsl:template>
<xsl:template match="data">
<xsl:apply-templates select="./row"/>
</xsl:template>
<xsl:template match="row">
<xsl:variable name="row_attributes" select="@*"/>
<xsl:variable name="column_count" select="position()"/>
<xsl:for-each select="/input/table/columns/column">
<xsl:variable name="row_name" select="@name"/>
<xsl:element name="row">
<xsl:attribute name="id">
<xsl:value-of select="position() * $column_count"/>
</xsl:attribute>
<xsl:attribute name="key">
<xsl:value-of select="@value"/>
</xsl:attribute>
<xsl:attribute name="value">
<xsl:for-each select="$row_attributes">
<xsl:if test="local-name(.) = $row_name">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:attribute>
</xsl:element>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list