-----Original Message-----
From: Smilen Dimitrov
I'm a newbie with XSL, and after long searching, and mainly
thanks to the information in the list, I finally managed to solve
the problem. Consider the following structure:
Hi,
This bit:
<xsl:for-each select="./*">
<xsl:sort select="count(child::*)" data-type="number"
order="descending"/>
<xsl:call-template name="ArrangeDirectory">
<xsl:with-param name="CurrentNode" select="."/>
</xsl:call-template>
</xsl:for-each>
would, with the given input, actually have exactly the same output as:
<xsl:apply-templates>
<xsl:sort select="count(*)" data-type="number"
order="descending" />
</xsl:apply-templates>
So the complete solution revised:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" indent="yes" />
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="node">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:apply-templates>
<xsl:sort select="count(*)" data-type="number"
order="descending" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Cheers,
Andreas
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