Do anyone of you know how to enable an item in a table
to go to next line without using <br/>
If you are doing the xsl, if you used
<xsl:value-of select="' '"/> in the table, it
won't works. It won't go to the next line.
Actually, it is calling a template which will replace
the character ',' in a string to '#10;' so that it
will go to next line. However, it didn't works.
The actual coding is like below:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xalan="http://xml.apache.org/xalan"
exclude-result-prefixes="xalan" >
<xsl:output method="html" indent="yes"
omit-xml-declaration="yes" encoding="UTF-8"/>
<xsl:template match="/">
<xsl:variable name="myString" select="'first message,
second, third'"/>
<xsl:variable name="myNewString">
<xsl:call-template name="replaceCharsInString">
<xsl:with-param name="stringIn"
select="string($myString)"/>
<xsl:with-param name="charsIn" select="', '"/>
<xsl:with-param name="charsOut"
select="' '"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="myNewRealString"
select="string($myNewString)"/>
<table width="100%" border="1" cellspacing="0"
cellpadding="0" bordercolor="#000000">
<tbody>
<tr>
<td>
<xsl:value-of
select="$myNewRealString"/>
</td>
</tr>
</tbody>
</table>
</xsl:template>
<xsl:template name="replaceCharsInString">
<xsl:param name="stringIn"/>
<xsl:param name="charsIn"/>
<xsl:param name="charsOut"/>
<xsl:choose>
<xsl:when test="contains($stringIn,$charsIn)">
<xsl:value-of
select="concat(substring-before($stringIn,$charsIn),$charsOut)"/>
<xsl:call-template name="replaceCharsInString">
<xsl:with-param name="stringIn"
select="substring-after($stringIn,$charsIn)"/>
<xsl:with-param name="charsIn"
select="$charsIn"/>
<xsl:with-param name="charsOut"
select="$charsOut"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$stringIn"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Ok. Hope to get the quick reply from you!!
Thanks a lot.
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